How many solutions does the systemhave?You can use the interactive graph below tofind the answer.y = 3x + 3y= –2x +3

To solve the system of equations we need to use elimination. But to do that we are required to rewrite the equations in implicit form.[tex]ax+by+c=0[/tex]So we have,[tex]3x-y+3=0 \\ -2x-y+3=0[/tex]Then multiply the first equation by 2 on both sides and second equation by 3 on both sides. Resulting with,[tex]6x-2y+6=0 \\ -6x-3y+9=0[/tex]Adding these two equations eliminates the first term in both since 6x - 6x = 0. Hence,[tex]-5y+15=0\Longrightarrow y=3[/tex]Now that we know the value of y we can insert it in either one of the equations in the system. I'll pick first one to get x.[tex]3=3x+3\Longrightarrow 3x=0\Longrightarrow x=0[/tex]So the solution to this system of equation are [tex]\boxed{x=0},\boxed{y=3}[/tex]Hope this helps.r3t40