Q:

HELP ASAPWhat are the coordinates of the vertices of the triangle after a dilation by a scale factor of 14, centered at the origin?U → U'V → V'W → W'

Accepted Solution

A:
Answer:
U' = (-1,2)
V' = (2,2)
W' = (0,-2)

Explanation:
The given dilation factor is 1/4
This means that each coordinate point is multiplied by 1/4 to get its dilated image.

For point U:
Point U = (-4,8)
x coordinate of U' = 1/4 * x coordinate of U
x coordinate of U' = 1/4 * -4 = -1
y coordinate of U' = 1/4 * y coordinate of U
y coordinate of U' = 1/4 * 8 = 2
This means that: U' = (-1,2)

For point V:
Point V = (8,8)
x coordinate of V' = 1/4 * x coordinate of V
x coordinate of V' = 1/4 * 8 = 2
y coordinate of V' = 1/4 * y coordinate of V
y coordinate of V' = 1/4 * 8 = 2
This means that: V' = (2,2)

For point W:
Point W = (0,-8)
x coordinate of W' = 1/4 * x coordinate of W
x coordinate of W' = 1/4 * 0 = 0
y coordinate of W' = 1/4 * y coordinate of W
y coordinate of W' = 1/4 * -8 = -2
This means that: W' = (0,-2)

Hope this helps :)